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Home/ Questions/Q 8638921
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Editorial Team
  • 0
Editorial Team
Asked: June 12, 20262026-06-12T10:51:52+00:00 2026-06-12T10:51:52+00:00

Basically I want it to stop and print a message if they’ve already added

  • 0

Basically I want it to stop and print a message if they’ve already added that person to the ArrayList, but it won’t do that.

Here’s the method:

@Override
    public boolean equals(Object o) {
        if (this.name == ((Student)o).getName() && this.ID == ((Student)o).getID()) {
            return true;
        }
        else {
            return false;
        }
    }

And the code section it’s used in:

public void addStudents() {
        Scanner keyboard = new Scanner(System.in);
        String name = "", ID = "";

        System.out.println("Welcome! Please type exit at any point to stop entering students and for the lottery to commence.\n");

        System.out.print("Student name: ");
        name = keyboard.nextLine();

        if (!name.equals("exit")) {
            System.out.print("Student ID: ");
            ID = keyboard.nextLine();
        }

        while (!name.equals("exit") && !ID.equals("exit")) {
            System.out.print("\nStudent name: ");
            name = keyboard.nextLine();

            if (!name.equals("exit")) {
                System.out.print("Student ID: ");
                ID = keyboard.nextLine();

                if (!ID.equals("exit")) {
                    boolean contains = false;

                    for (int i = 0; i < students.size(); i++) {
                        if (students.get(i).equals((new Student(name, ID)))) {
                            contains = true;
                        }
                    }

                    if (!contains) {
                        students.add(new Student(name, ID));
                    }
                    else {
                        System.out.println("You can only enter once.");
                    }
                }
            }
        }
    }

I’ve toiled over this for quite awhile, but can’t put my finger on why it won’t work.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-12T10:51:53+00:00Added an answer on June 12, 2026 at 10:51 am

    Use the equals() method to compare strings, not ==

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