Home/ Questions/Q 6823167
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Asked: 2026-05-26T21:45:01+00:00

Basically I’m trying to parse my template with preg_replace by finding anything that looks

  • 0

Basically I’m trying to parse my template with preg_replace by finding anything that looks like {$variable} on the HTML file.

public function parse_file($file) {

    return preg_replace('/{\$(.+?)}/i', "$this->params[$1]", $this->get_file($file));

}

However, this is returning Array(variable), instead of whatever variable is set to in the $this->params array.

I’d like it to return $this->params['variable'].

To clarify, this is what my HTML file looks like.

<!DOCTYPE html>
<html>
    <head>
        <title>{$variable}</title>
        <meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
    </head>
    <body>
        <div>TODO write content</div>
    </body>
</html>
Share

Leave an answer

You must login to add an answer.

Need An Account,

1 Answer

  1. Editorial Team

    Try preg_replace_callback() instead, eg (PHP 5.3)

    // using $this in an anonymous function is not very well defined
$params = $this->params;

return preg_replace_callback($pattern, function (array $matches) use ($params) {
    return $params[$matches[1]];
}, $this->get_file($file));
    • 0