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Home/ Questions/Q 6585199
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T16:37:55+00:00 2026-05-25T16:37:55+00:00

Basically I’ve read in 5 bytes that correspond to a quantity, but I would

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Basically I’ve read in 5 bytes that correspond to a quantity, but I would like to convert it to a Word64. What’s the best way to do this?

Edit: I should also say that this is run in an inner loop so performance is critical. Ideally
I’d like to do something like:

uint64_t word = 0;
char bytes[5] = getbytes(5)
word += (bytes[0] << 32) 
        + (bytes[1] << 24) 
        + (bytes[2] << 16) 
        + (bytes[3] << 8) 
        + (bytes[4])

Or something similar.

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  1. Editorial Team
    Editorial Team
    2026-05-25T16:37:56+00:00Added an answer on May 25, 2026 at 4:37 pm

    If you just want a simple function, assuming big-endian byte order, this one should do the job:

    foo :: B.ByteString -> Word64
    foo = B.foldl' (\x y -> x * 256 + fromIntegral y) 0
    

    However, if you are reading lots of binary data, you might want to look into using the binary package.

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