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Home/ Questions/Q 7505599
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Editorial Team
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Editorial Team
Asked: May 29, 20262026-05-29T21:58:14+00:00 2026-05-29T21:58:14+00:00

Basically, this peice of code seems to behaving differently when I move the breakpoints

  • 0

Basically, this peice of code seems to behaving differently when I move the breakpoints

    int checker = something.length(); /* something is the value of an edittext */

    boolean badInput = false;

    if(checker == 0)
    {
        badInput = true;
    }

    if(checker > 12)
    {
        badInput = true;
    }

*1  if(badInput = false)
    {
*2      /* A lot of 
               code to do 
               if the 
               input is GOOD */
    }
    else
    {
            /* Alert that the input is BAD */
    }

When I enter a 2 digit number into the edittext with the first breakpoint (1), badInput gives false, as it should.

Here is the problem: when I do exactly the same with only the second breakpoint (2), the code goes onto the else statement, and alerts, even though the input is exactly the same.

Anybody know why this might be?

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  1. Editorial Team
    Editorial Team
    2026-05-29T21:58:15+00:00Added an answer on May 29, 2026 at 9:58 pm

    This:

    if(badInput = false)
    

    Should be:

    if(badInput == false)
    

    Or preferrably:

    if (!badInput)
    

    The first is performing an assignment, not a comparison. The overall result of the expression badInput = false is also the value assigned (false) so it will never enter the body of that if.

    It’s not really clear what you mean by entering data “with” a breakpoint, but fundamentally the problem is in your code.

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