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Home/ Questions/Q 8136331
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Editorial Team
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Editorial Team
Asked: June 6, 20262026-06-06T10:43:42+00:00 2026-06-06T10:43:42+00:00

Basically what I have is this: secondData = [[8:33:00, 5], [8:33:01, 3], …] #

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Basically what I have is this:

secondData = [["8:33:00", 5], ["8:33:01", 3], ...] # and so forth
minuteData = [["8:33:00", 6], ["8:34:00", 5], ...] # and so forth

Now pretend like the time is an actual datetime object

What I want to do is find the most efficient method for iterating through the minute data and getting all the contained second data for that minute. e.g. if I have “8:34:00” I want “8:34.00″..”8:34:59”. Is there an easy way to make a list filter for this or something?

I should note that the lists are arranged in order of time, however there might be missing second data. I might only have 33 data points for the minute 9:58 for example.

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  1. Editorial Team
    Editorial Team
    2026-06-06T10:43:44+00:00Added an answer on June 6, 2026 at 10:43 am

    Use bisect.

    from bisect import bisect_left
    secondData[bisect_left(secondData, "8:33:00"):bisect_left(secondData, "8:34:00")]
    

    This will give you the slice of secondData for the half-open interval [“8:33:00”..”8:34:00″).

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