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Home/ Questions/Q 6052289
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T07:54:44+00:00 2026-05-23T07:54:44+00:00

Basically what I want to do is: urlpatterns = patterns(”, url(r’^old/site/url.php?someshit=(?P<id>\d+)’, ‘website.views.redirect_php’), ) But

  • 0

Basically what I want to do is:

urlpatterns = patterns('',
    url(r'^old/site/url.php?someshit=(?P<id>\d+)', 
    'website.views.redirect_php'),
)

But I always get a 404 ..

I’ve also tried to escape it like this

urlpatterns = patterns('',
    url(r'^old/site/url\.php\?someshit\=(?P<id>\d+)', 
    'website.views.redirect_php'),
)

No luck.

Any ideas ?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-23T07:54:44+00:00Added an answer on May 23, 2026 at 7:54 am

    What you’re doing does not work because GET parameters are not included in the string being matched by URLconf. (See What the URLconf searches against.)

    To achieve the desired behaviour, you’ll need to extract the GET parameter from within the view and redirect according.

    urlpatterns = patterns('',
        url(r'^old/site/url\.php$',
            view='website.views.redirect_php', 
            name='redirect_php'
        ),
    )
    

    and in your view:

    def redirect_php(request):
        id = request.GET.get("somesheet", None)
        if id == None:
            # handle case where "somesheet=?" was not provided
        else:
            # handle redirects based on id
    
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