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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T21:52:24+00:00 2026-05-13T21:52:24+00:00

Basically what I’m trying to do is have a picture rotate using mouse events.

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Basically what I’m trying to do is have a picture rotate using mouse events. For example, while you hold down the left mouse button, the picture rotates when you move the mouse up and down. I found another question on here almost like mine (How do I rotate a picture in C#) but when mapping the angle parameter in the rotate method (method source code in link) to the calculated angle between the mouse and the center of the image I get an overflow exception thrown. The image I’m trying to rotate is in a picture box. Any ideas? Should I be doing this another way?

Thanks in advance!

———EDIT 1———–

Ok I think my trig was off, I changed it to…

Angle = Atan((mousePosY – imageCenterY)/(mousePosX – imageCenterX)

But now the image doesn’t rotate, it just moves (I programmed the ability for it to move as well but that works fine). Here’s the piece of code I’m dealing with.

    private void pictureBox_MouseDown(object sender, MouseEventArgs e)
    {
        isDragging = true;

        pbCurrentX = e.X;
        pbCurrentY = e.Y;

    }

    private void pictureBox_MouseMove(object sender, MouseEventArgs e)
    {
        // For moving the image
        if (isDragging)
        {
            this.pictureBox1.Top = this.pictureBox1.Top + (e.Y - pbCurrentY);
            this.pictureBox1.Left = this.pictureBox1.Left + (e.X - pbCurrentX);
        }

        // For rotating the image
        if (rotateMode  && isDragging)
        {
            y2 = e.Y;
            y1 = (this.pictureBox1.Location.Y + (this.pictureBox1.Height / 2));
            x2 = e.X;
            x1 = (this.pictureBox1.Location.X + (this.pictureBox1.Width / 2));

            angle = (float)Math.Atan((y2-y1)/(x2-x1));

            // RotateImage method from the other question linked above
            this.pictureBox1.Image = RotateImage(this.pictureBox1.Image, angle);
        }


    }

The rotateMode flag is set to true when the pictureBox is double clicked. Thanks all!

———ANSWER———–

Thanks to Gabe I found all of the little kinks in my code and it works fine now. Only thing is I had to make the size of the picture box larger to fit the rotated image. Here is the correct code for everyone who wants to know the answer.

private void pictureBox_MouseDown(object sender, MouseEventArgs e)
    {
        isDragging = true;

        pbCurrentX = e.X;
        pbCurrentY = e.Y;

    }

    private void pictureBox_MouseMove(object sender, MouseEventArgs e)
    {

        if (isDragging && !rotateMode)
        {
            this.pictureBox1.Top = this.pictureBox1.Top + (e.Y - pbCurrentY);
            this.pictureBox1.Left = this.pictureBox1.Left + (e.X - pbCurrentX);
        }

        if (rotateMode  && isDragging)
        {
            y2 = e.Y;
            y1 = (this.pictureBox1.Location.Y + (this.pictureBox1.Height / 2));
            x2 = e.X;
            x1 = (this.pictureBox1.Location.X + (this.pictureBox1.Width / 2));

            angle = (float)Math.Atan2((y1 - y2), (x1 - x2));

            pictureBox1.Image =  RotateImage(currentImage, (100*angle));
        } 

    }

    private void pictureBox_MouseUp(object sender, MouseEventArgs e)
    {
        isDragging = false;
    }

Thanks Gabe and everyone else!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-13T21:52:24+00:00Added an answer on May 13, 2026 at 9:52 pm

    Have you tried something along the lines of this.pictureBox1.Image = RotateImage(this.pictureBox1.Image, angle);? The RotateImage function you linked to returned a new rotated image rather than rotating it in-place as your code expects.

    Unfortunately, doing that rotates an already-rotated image. What you need to do is have the original image stored somewhere, say originalImage. Then have this.pictureBox1.Image = RotateImage(originalImage, angle);. That way it always rotates a fresh version of the original.

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