Question

been searching everywhere, but couldn’t the correct answer.

the problem is pretty simple:

i have to convert ASCII integer values into char’s.
for example, according to ASCII table, 108 stands for ‘h’ char. But when i try to convert it like this:

int i = 108
char x = i

and when I printf it, it shows me ‘s’, no matter what number i type in(94,111…).

i tried this as well:

int i = 108;
char x = i + '0'

but i get the same problem! by the way, i have no problem in converting chars into integers, so i don’t get where’s the problem :/
thanks in advance

Answer 1

That is how you do it. You probably want it unsigned, though.

Maybe your printf is wrong?

The following is an example of it working:

// Print a to z.
int i;
for (i = 97; i <= 122; i++) {
    unsigned char x = i;
    printf("%c", x);
}

This prints abcdefghijklmnopqrstuvwxyz as expected. (See it at ideone)

Note, you could just as well printf("%c", i); directly; char is simply a smaller integer type.

If you’re trying to do printf("%s", x);, note that this is not correct. %s means print as string, however a character is not a string.

If you do this, it’ll treat the value of x as a memory address and start reading a string from there until it hits a \0. If this merely resulted in printing s, you’re lucky. You’re more likely to end up getting a segmentation fault doing this, as you’ll end up accessing some memory that is most likely not yours. (And almost surely not what you want.)