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Home/ Questions/Q 3758420
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Editorial Team
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Editorial Team
Asked: May 19, 20262026-05-19T10:09:33+00:00 2026-05-19T10:09:33+00:00

Before I do this myself I thought I’d ask here and see if there

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Before I do this myself I thought I’d ask here and see if there are any quick solutions.

I don’t need the history-lookup, autocomplete, or other fancy features of Chrome’s omnibar; I just need to detect if a string looks like a valid URL (with valid TLDs and scheme/protocol) or ip-address (IPV4 and IPV6).

I’m not sure how to search chrome’s code repository for a look at how they do it. So if you can find that for me that would be an acceptable answer (bonus points if you port it to javascript!).

Tagged as language-agnostic because I don’t care what language it is in [well, please no Ook or LOLCODE]). Javascript will be the final implementation, though.

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  1. Editorial Team
    Editorial Team
    2026-05-19T10:09:33+00:00Added an answer on May 19, 2026 at 10:09 am

    There’s a regex provided in RFC2396 – Uniform Resource Identifiers (URI): Generic Syntax (see appendix B) :

    The following line is the regular
    expression for breaking-down a URI
    reference into its components.

      ^(([^:/?#]+):)?(//([^/?#]*))?([^?#]*)(\?([^#]*))?(#(.*))?
       12            3  4          5       6  7        8 9
    

    The numbers in the second line
    above are only to assist readability;
    they indicate the reference points for
    each subexpression (i.e., each
    paired parenthesis). We refer to the
    value matched for subexpression
    as $. For example, matching the
    above expression to

      http://www.ics.uci.edu/pub/ietf/uri/#Related
    

    results in the following
    subexpression matches:

      $1 = http:
      $2 = http
      $3 = //www.ics.uci.edu
      $4 = www.ics.uci.edu
      $5 = /pub/ietf/uri/
      $6 = <undefined>
      $7 = <undefined>
      $8 = #Related
      $9 = Related
    

    I don’t see a reason to not use regex in this case, especially if you’re just checking if it’s a URI or if it’s a search.

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