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Home/ Questions/Q 6689295
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T05:30:09+00:00 2026-05-26T05:30:09+00:00

Before inserting into the database, I’m using the following code to check for duplicates.

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Before inserting into the database, I’m using the following code to check for duplicates. To me, a duplicate is only considered a duplicate when name, description, price, city, and enddate match.

foreach($states_to_add as $item) {
    $dupesql = "SELECT 
                    COUNT(*) 
                FROM 
                    table 
                WHERE 
                    (   
                        name = '$name' 
                        AND description = '$description' 
                        AND manufacturer = '$manufacturer' 
                        AND city ='$city' 
                        AND price = '$price' 
                        AND enddate = '$end_date'
                    )";

    $duperaw = mysql_query($dupesql);

    if($duperaw > 0) {
        echo nl2br("$name already exists in $city \n");
    } 
    else {
        $sql = "INSERT INTO table (..... (here go the values to be inserted)
        ....

Each value is defined prior to running through this checking, my result always comes back as item already exists. I dumped “dupesql” and copy/pasted the command into phpmyadmin which comes back with count 0.

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  1. Editorial Team
    Editorial Team
    2026-05-26T05:30:09+00:00Added an answer on May 26, 2026 at 5:30 am

    You want to do the following:

    $dupesql = "SELECT * FROM table where (name = '$name' AND description = '$description' AND manufacturer = '$manufacturer' AND city ='$city' AND price = '$price' AND enddate = '$end_date')";
    
    $duperaw = mysql_query($dupesql);
    
    if (mysql_num_rows($duperaw) > 0) {
      //your code ...
    }
    

    See Here for more information.

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