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Home/ Questions/Q 9234965
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T06:54:49+00:00 2026-06-18T06:54:49+00:00

Before of the latest update, i wrote this code for example <input type=text id=link>

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Before of the latest update, i wrote this code for example

<input type="text" id="link">
<p> {{variable}} </p>
// other code
var input = query('#link');
var variable = input.value;

This snippet of code still work, but anyone know why the editor reports this message?

"value" in not a member of Element
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  1. Editorial Team
    Editorial Team
    2026-06-18T06:54:50+00:00Added an answer on June 18, 2026 at 6:54 am

    The Dart Editor reports that, because it thinks input variable is an instance of Element. Why? Because query() always returns an element, but the editor can’t know that in your case, it’s an input (of type InputElement).

    You can ignore the warning. The IDE just can’t know that the queried result is an InputElement, unless you tell it:

    InputElement input = query('#link');
    

    or I think this also works:

    var input = query('input#link');
    

    If you really want to tell the Dart runtime that you expect a variable to be of a certain type, you can use the cast operator: as. This has the advantage of informing the editor of the expected type, and it will also throw an error if the variable is not of the expected type.

    var input = query('#link') as InputElement;
    

    Note that Dart is a dynamic language, so I caution against using as unless you think other developers might be confused about your intent.

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