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Home/ Questions/Q 558803
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T12:10:13+00:00 2026-05-13T12:10:13+00:00

Before using google collections I had something similar to next code: private Set<A> aSet

  • 0

Before using google collections I had something similar to next code:

private Set<A> aSet = ...;
private Set<B> bSet = ...;

public Foo getFoo (Map<?, List<Bar>> bars, Set<?> set) {
   for (Object item : set) {
      for (Bar bar : bars.get (item)) {
          //build foo;
      }
   }
   ...
}

and I was able to make calls like these:

Map<A, List<Bar> aMap = getAMap ();
Foo f1 = getFoo (aMap, aSet);
Map<B, List<Bar> bMap = getBMap ();
Foo f2 = getFoo (bMap, bSet);

Now, with Multimap, I cannot do the same:

public Foo getFoo (Multimap<?, List<Bar>> bars, Set<?> set) {
   for (Object item : set) {

      // compile error: get(capture#621 of ?) in Multimap ... cannot be applied to java.lang.Object
      for (Bar bar : bars.get (item)) {
          //build foo;
      }
   }
   ...
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-13T12:10:13+00:00Added an answer on May 13, 2026 at 12:10 pm

    Try this:

    public <T> Foo getFoo (Multimap<T, List<Bar>> bars, Set<T> set) {
       for (T item : aSet) {
    
          // compile error: get(capture#621 of ?) in Multimap ... cannot be applied to java.lang.Object
          for (Bar bar : bars.get (item)) {
             //build foo;
          }
       }
       ...
    }
    

    EDIT:

    If you see the javadoc for both classes, you will realize that the javadoc for Map is:

    V get(Object key) 
    

    and for MultiMap is:

    Collection<V> get(K key) 
    

    See that the parameter for Map is not generified.

    The MultiMap is better for generic, but Map is designed so it has backward compability with previous Map from Java 1.4.

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