being a Cocoa/Obj-C newbie I am going through the “Cocoa Programming for Mac OS X” book by Aaron Hillegass and – leaving apart the fact that now we have also the chance to use GC to avoid all this reasoning – I am not sure I get the reason for some of those retains.
In particular in one of the examples Aaron gives as good programming practice:
- (void) setFoo:(NSCalendarDate *)x
{
[x retain];
[foo release];
foo = x;
}
I don’t get the reason for retaining the x instance at the first line of the method:
[x retain];
The scope of this instance is just the set method, right?
When exiting the method scope the x instance should be deallocated anyway no?
Besides, when assigning x to foo with:
foo = x;
foo will be anyway pointing to x memory cells and will therefore increment the pointed object retain count, no? This should ensure the memory won’t be deallocated.
So, what’s the point? I am sure I am missing something, of course, but don’t know what exactly.
Thanks,
Fabrizio
Retain means: I will be needing this object to stay around, it must not be deallocated. If
xwouldn’t be retained, the following is likely to happen:You assign
xtofoo, sofoonow points to the address where your NSCalendarDate is. Someone releases or autoreleases this object, it’s retain count eventually drops to 0 and the object is deallocated. Now yourfoostill points to that address, but there’s no longer a valid object. Sometime later, a new object is created and by chance it’s situated at the same address than your old NSCalendarDate object. Now yourfoopoints to an entirely different object !To prevent that, you need to
retainit. You need to say, please do not deallocate the object yet, I need it. Once you’re done with it, youreleaseit which means I no longer need the object, you can clean it up now if nobody else needs it.Now for the classical three part assignment. Consider your
setFoo:would look like this:This is a very bad idea. Consider your object is the only one who has retained the NSCalendarDate object, and consider you would then do:
[self setFoo:foo];. Might sound silly, but something like this can happen. The flow would now be this:foowould be released. Its retain count might now drop to 0 and the object will get deallocated.This is why you always first
retainthe new object, thenreleasethe old object.If you’re coming from a Java or .NET background, it is very important to understand that a variable of type
Foo *only contains the address of your object, nothing more. In Java or .NET, a variable that points to an object automatically “retains” it, if you will. Not so in Objective-C (in non-GC environments). You could consider a variable of typeFoo *to be a weak reference, and you explicitly need to tell Objective-C whether you will still need that object at that address or not.