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Home/ Questions/Q 7759731
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T13:42:18+00:00 2026-06-01T13:42:18+00:00

Being new to c++ I’ve been practicing with questions. One program I wrote includes

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Being new to c++ I’ve been practicing with questions. One program I wrote includes the use of structs and arrays:

#include <iostream>
using namespace std;

int main (void){
struct CandyBar{
    char brandName[200];
    float weight;
    int calories;
};

CandyBar snacks[3] = {
    {"Cadbury's Flake",23.5,49},
    {"Cadbury's Wispa",49.3,29},
    {"Cadbury's Picnic",57.8,49},
};

for(int i=0;i<3;i++){
    cout << "Brand Name: " << snacks[i].brandName << endl;
    cout << "Weight: " << snacks[i].weight << endl;
    cout << "Calories: " << snacks[i].calories << endl;
    snacks++;
}

cin.get();
return 0;
}

The above program fails becuase of the “snacks++”, but I can’t understand why. As I understand arrays they are made of two parts the pointer (“snacks”) and the object ([]), so shouldn’t the “snacks++” work as I am incrementing the pointer?

Thanks
Dan

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  1. Editorial Team
    Editorial Team
    2026-06-01T13:42:19+00:00Added an answer on June 1, 2026 at 1:42 pm

    just remove the snacks++;
    you are already using the variable i as a index in the array.

    if you do want to use a pointer arithmetics:
    a. you should define a pointer to the start of the array and work with it rather then work with the array.
    b. you should use a pointer instead of the array with index i when accessing the data.

    struct CandyBar* ptr = snacks;
    for(int i=0;i<3;i++){
        cout << "Brand Name: " << ptr->brandName << endl;
        cout << "Weight: " << ptr->weight << endl;
        cout << "Calories: " << ptr->calories << endl;
        ptr++;
    }
    
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