Question

below I have a query that will get the most common user agents for a site from a table of user agents and a linked table of ip addresses:

SELECT count(*) as num, string FROM `useragent_ip`
left join useragents on useragent_id = useragents.id
group by useragent_id
having num > 2
order by num desc, string

Sometimes it will show me something like

25 Firefox
22 IE
11 Chrome
3  Safari
1  Spider 1
1  Spider 2
1  Spider 3

My question is if there is a way that since the numbers on the left represent percentages of a whole, and will grow with time, can I have part of the sql statement to show each group’s percentage of the whole? So that instead of using having num > 2 then I could do something that would say get the percentage of the total rows instead of just the number of rows?

Answer 1

Yes you can:

select num, string, 100 * num / total as percent
from (
    select count(*) as num, string
    from useragent_ip
    left join useragents on useragent_id = useragents.id
    group by useragent_id) x
cross join (
    select count(*) as total
    from useragent_ip
    left join useragents on useragent_id = useragents.id) y
order by num desc, string;

I removed the having num > 2, because it didn’t seem to make sense.