Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 8954583
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: June 15, 20262026-06-15T14:20:29+00:00 2026-06-15T14:20:29+00:00

Below is a piece of code copied from a website . The value set

  • 0

Below is a piece of code copied from a website.
The value set for the direction prints the respective character from “nsew”. For example the output of this code is character w.

I am wondering how does it work.

#include<stdio.h>
void main (void){
   int direction = 3;
   char direction_name = direction["nsew"];
   printf("%c",direction_name);
}
  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-06-15T14:20:30+00:00Added an answer on June 15, 2026 at 2:20 pm

    This is because the array subscript operator is commutative, i.e., this:

    const char *p = "Hello";
    char x = p[0];
    

    Is equivalent to

    const char *p = "Hello";
    char x = 0[p];
    

    Weird, huh? In your case you are indexing into the third position of the string literal (which is an array) "nsew".

    some_ptr[n] is equivalent to *(some_ptr + n), and since addition is commutative, it is also equivalent to *(n + some_ptr). It then follows that n[some_ptr] is also an equivalent expression.

    I wouldn’t recommend using this “feature” however… seriously, don’t do it.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I have a piece of matlab code below which reads data from a table.
I know the piece of code below is far from perfect but it does
I have a piece of code, copied below, with really similar structs in which
From the below piece of code, why I am getting Reading Socket for response
Below is a piece of code from Python which has been bothering me for
Below is a small piece of code that copies 4 elements from an array
In the below piece of code, theta x and y are varying smoothly for
I really can't understand how the below piece of code is working... options.each {
I have a piece of code (below) that can get the text of an
Firstly sorry for the long piece of code pasted below. This is my first

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.