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Home/ Questions/Q 6873117
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T04:01:02+00:00 2026-05-27T04:01:02+00:00

Below is a program in Scala. def range(low : Int, high : Int) :

  • 0

Below is a program in Scala.

def range(low : Int, high : Int) : List[Int] = {
    var result : List[Int] = Nil
    result = rangerec(root, result, low, high)
    result
}

private def rangerec(r : Node, l : List[Int], low : Int, high :Int) : List[Int] = {
      var resultList : List[Int] = List()
      if(r.left != null) {
        rangerec(r.left, resultList, low, high)
      } else if(r.right != null) {
        rangerec(r.right, resultList, low, high)
      } else {
        if(r.key >= low && r.key <= high) {
            resultList = resultList ::: List(r.key)
            resultList
        } 
      }
      resultList
}

I made range method in my binary search tree, implementing in-order traversal algorithm. So it has to work recursively, but it doesn’t print anything, List(). How to fix my algorithm? or edit my code?

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  1. Editorial Team
    Editorial Team
    2026-05-27T04:01:03+00:00Added an answer on May 27, 2026 at 4:01 am

    I don’t know scala, but you need to use list l passed as a parameter into recursive function and use output from rangerec function.

    private def rangerec(r : Node, l : List[Int], low : Int, high :Int) : List[Int] = {
          var resultList : List[Int] = l
          if(r.left != null) {
            resultList = rangerec(r.left, l, low, high)
          } else if(r.right != null) {
            resultList = rangerec(r.right, l, low, high)
          } else {
            if(r.key >= low && r.key <= high) {
                resultList = l ::: List(r.key)
            } 
          }
          resultList
    }
    
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