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Home/ Questions/Q 6376817
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T01:47:34+00:00 2026-05-25T01:47:34+00:00

Below is a pure function f for which f(a) !== f(b) despite a ===

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Below is a pure function f for which f(a) !== f(b) despite a === b (notice the strict equalities) for some values of a and b:

var f = function (x) {
   return 1 / x;
}

+0 === -0 // true
f(+0) === f(-0) // false

The existence of such functions can lead to difficult-to-find bugs. Are there other examples I should be weary of?

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  1. Editorial Team
    Editorial Team
    2026-05-25T01:47:34+00:00Added an answer on May 25, 2026 at 1:47 am

    Yes, because NaN !== NaN.

    var f = function (x) { return Infinity - x; }
    
    Infinity === Infinity // true
    f(Infinity) === f(Infinity) // false
    
    f(Infinity) // NaN
    

    Some other examples that yield NaN whose arguments can be strictly equal:

    0/0
    Infinity/Infinity
    Infinity*0
    Math.sqrt(-1)
    Math.log(-1)
    Math.asin(-2)
    
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