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Home/ Questions/Q 8711523
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T04:53:56+00:00 2026-06-13T04:53:56+00:00

Below is my code (don’t worry about ‘off’, it’s the offset based on the

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Below is my code (don’t worry about ‘off’, it’s the offset based on the where the user clicks). In the second line I am trying to clone an existing div and then show the cloned copy? But it doesn’t work. However if I remove clone() then the code does work, but of course it simply shows the existing div which isn’t what I need.

var off = $(this).offset();
var div = $('#testtt').clone();
div.css({ position: "absolute", top: off.top, left: off.left });
div.show();

Any tips?

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  1. Editorial Team
    Editorial Team
    2026-06-13T04:53:57+00:00Added an answer on June 13, 2026 at 4:53 am

    You are cloning the div but not inserting it anywhere in your DOM..

    So it is non existent until you do that

    var off = $(this).offset();
    var div = $('#testtt').clone();
    div.css({ position: "absolute", top: off.top, left: off.left });
    
    $('body').append(div);   <-- Appending to body here.. You can append anywhere you want
    
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