below is my Jquery slider range (min-max) code, the drag works fine on desktop

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Asked: June 9, 20262026-06-09T21:18:13+00:00 2026-06-09T21:18:13+00:00

below is my Jquery slider range (min-max) code, the drag works fine on desktop

0

below is my Jquery slider range (min-max) code, the drag works fine on desktop computer, but when I test this on iPad, it doesn’t work. Can anyone help me with this please?

Unfortunately I can’t attach image. Below is the diagram of slider range,

=====(>)=======(<)=====

var maxValue,myRequest,isDown=false,setUrl;
setUrl = "/search_type/filter.php";

$( "#slider-range" ).slider({
    range: true,
    min: 0,
    max: 500,
    step:25,
    orientation: "horizontal",
    values: [ 0,500 ],
    slide: function( event, ui ) {

    if(ui.values[1] === 500)
    {
        maxValue = 500+"+";
    }
    else
    {
        maxValue = ui.values[1];
    }
        $( "#priceRange" ).val( "£" + ui.values[ 0 ] + " to £" + maxValue );
    }
});

// AJAX CALL 
$("#slider-range").find('a').mousedown(function(){
    isDown=true;
});
$(document).mouseup(function(){
    if(isDown)
    {
        return setAjaxRequest();
    }
});

// Decoration drag image
$( "#slider-range" )
.find('.ui-slider-handle')
.eq(0).addClass('a-right').end()
.eq(1).addClass('a-left');

//Default this is 
    $( "#priceRange" )
    .val( "£" + $( "#slider-range" )
    .slider( "values", 0 ) + " to £" + $( "#slider-range" )
    .slider( "values", 1 )+'+');
    return true;