Question

Below is the code from one of my php files. It seems to have compilation errors. I am new to php.

Can anyone please tell me whats wrong below in php function code:

function eshop_extras_checkout($echo){


    $echo .= '<script>

    $(".formGroup").hide();
$('#chooseForm input:checkbox').on('change', function() {
    if($(this).is(':checked')) {
        $("#" + $(this).val()).show();
    }
    else {
        $("#" + $(this).val()).hide();
    }   
});
​   
    </script>';

    $echo .= '<fieldset class="eshop eshop_extra">' . "\n";


     $echo .= ' <form id="chooseForm">
    <input type="checkbox" name="form1" value="form1"> Form1<br>
    <input type="checkbox" name="form1" value="form2"> Form2<br>
</form>

<form id="form1" class="formGroup">
    <h2>FORM 1</h2>
    <label>Name</label><input type="text"> <br>
    <label>Address</label><input type="text">
</form>

<form id="form2" class="formGroup">
    <h2>FORM 2</h2>
    <label>Username</label><input type="text"> <br>
</form>';


    $echo .= '<legend>Articles Order Form</legend>' . "\n";



    return $echo;


}

This is the error in my browser:

Parse error: syntax error, unexpected T_IF in /home/harris12/public_html/somedomain.com/wp-content/plugins/eshop-extras/eshop-extras.php on line 43

Answer 1

Try it like this:

 <?php
function eshop_extras_checkout($echo){


    $echo .= '<script>

    $(".formGroup").hide();
    $("#chooseForm input:checkbox").on("change", function() {
        if($(this).is(":checked")) {
            $("#" + $(this).val()).show();
        }
        else {
            $("#" + $(this).val()).hide();
        }
    });
    ​
</script>';

    $echo .= '<fieldset class="eshop eshop_extra">' . "\n";


    $echo .= ' <form id="chooseForm">
        <input type="checkbox" name="form1" value="form1"> Form1<br>
        <input type="checkbox" name="form1" value="form2"> Form2<br>
    </form>

    <form id="form1" class="formGroup">
        <h2>FORM 1</h2>
        <label>Name</label><input type="text"> <br>
        <label>Address</label><input type="text">
    </form>

    <form id="form2" class="formGroup">
        <h2>FORM 2</h2>
        <label>Username</label><input type="text"> <br>
    </form>';


    $echo .= '<legend>Articles Order Form</legend>' . "\n";



    return $echo;
}
    ?>

You should have either escaped the apostrophes or used double quotes.