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Editorial Team
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Asked: 2026-06-12T11:28:11+00:00

Below is xml file format from which words to be searched. <Book> <Page id=1>

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Below is xml file format from which words to be searched.

<Book>
<Page id="1">
<Head>Preface</Head>
<Body>
<Paragraph>
    <Line>
        <Word>
            <Char>T</Char>
            <Char>h</Char>
            <Char>i</Char>
            <Char>s</Char>
        </Word>
        <Word>
            <Char>-</Char>
        </Word>
        <Word>
            <Char>i</Char>
            <Char>s</Char>
        </Word>
        <Word>
            <Char>-</Char>
        </Word>
        <Word>
            <Char>s</Char>
            <Char>a</Char>
            <Char>m</Char>
            <Char>p</Char>
            <Char>l</Char>
            <Char>e</Char>
        </Word>
        <Word>
            <Char>-</Char>
        </Word>
        <Word>
            <Char>t</Char>
            <Char>e</Char>
            <Char>x</Char>
            <Char>t</Char>
        </Word>
    </Line>
</Paragraph>
</Body>
</Page>

I used the below XPath expressions in C# to find values of Char Node.

XmlDocument objXmlDoc = new XmlDocument();
XmlNodeList objXmlNodeList;
objXmlDoc.Load(sFilePath);
objXmlNodeList = objXmlDoc.SelectNodes("//CHAR[translate(text(),'abcdefghijklmnopqrstuvwxyz','ABCDEFGHIJKLMNOPQRSTUVWXYZ')='" + txtFindText.Text.ToUpper() + "']");

Here, how to get a complete word with XPath from above XML File ?

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1 Answer

  1. Editorial Team

    It is not possible theoretically. The reason is that XML/XPATH does not ensure order as the result of a query is a “node-set” which by definition is “an unordered collection of nodes without duplicates”.

    http://www.w3.org/TR/xpath/

    Nevertheless, you can get close to the requirement. For example, you can get the first word:

    XmlDocument objXmlDoc = new XmlDocument();
XmlNodeList objXmlNodeList;
objXmlDoc.Load(sFilePath);
objXmlNodeList = objXmlDoc.SelectNodes("//Word");
string s = string.Empty;
XmlNodeList wordNodes = objXmlNodeList[0].ChildNodes;
foreach (XmlNode characterNode in wordNodes)
{
   s = s + characterNode.InnerText;
}
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