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Asked: 2026-06-01T05:16:44+00:00

Below mentioned is my XML, <?xml version=1.0 encoding=utf-8?> <soap:Envelopexmlns:soap=http://schemas.xmlsoap.org/soap/envelope/xmlns:xsi=http://www.w3.org/2001/XMLSchema-instancexmlns:xsd=http://www.w3.org/2001/XMLSchema> <soap:Body> <Response xmlns=http://tempuri.org/> <Result> <mp_response>

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Below mentioned is my XML,

<?xml version="1.0" encoding="utf-8"?>
<soap:Envelopexmlns:soap="http://schemas.xmlsoap.org/soap/envelope/"xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<soap:Body>
<Response xmlns="http://tempuri.org/">
<Result>
    <mp_response>
        <data signature="something">
                  <outcome errorcode="0" errordescription="" errorsolution=""/>
                 something
</data>
</mp_response>
</Result>
</Response>
</soap:Body>
</soap:Envelope>

I wish to extract the “errorcode” from this XML.
How I am suppose to do that ?
Please help.

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1 Answer

  1. Editorial Team

    If your target devices support SAX from JSR 172, you should go with this parser. It will reduce your app’s final jar size (no libs imported). There is a good sample at http://www.developer.nokia.com/Community/Wiki/JSR_172:_XML_Parsing_Example It actually unmarshalls the XML into Java objects.

    After you feel confident you may try my generic approach to unmarshalling in Java ME at http://smallandadaptive.blogspot.com.br/2010/11/xml-data-binding.html

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