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Editorial Team
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Asked: 2026-06-03T18:59:18+00:00

Below query expression: SELECT distinct xmlCol.value(‘(//interest/@id)[1]’,’nvarchar(64)’) FROM table1 Returns a list of id of

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Below query expression:

SELECT distinct xmlCol.value('(//interest/@id)[1]','nvarchar(64)') FROM table1

Returns a list of id of first interest element of all records.

But an xml may contains multiple interest elements.

So, how to get a distinct list of all interest elements of all records in sql xquery ?

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1 Answer

  1. Editorial Team
    select distinct T.N.value('.','nvarchar(64)')
from table1
  cross apply xmlCol.nodes('//interest/@id') as T(N)
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