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Asked: 2026-05-31T12:48:45+00:00

Belows are the xml data stored in a field call xmldoc with data type

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Belows are the xml data stored in a field call xmldoc with data type XMLTYPE and the pattern are stored in each record.

The first row(record) of the xmldoc field should be:

<cdata>
<r> <year>2009</year>
<month>Jan</month>
<day>1</day>
<data>1180</data>
</r>
</cdata>

and the second row of the xmldoc field should be:

<cdata>
<r>
<year>2009</year>
<month>Jan</month>
<day>2</day>
<data>1280</data>
</r>
</cdata>

and the belowed xml datas are also modified into the upper example (each data stored in a row record in xmldoc field and embedded a ‘cdata’ root element.)

<r>
<year>2009</year>
<month>Jan</month>
<day>3</day>
<data>1380</data>
</r>
<r>
<year>2009</year>
<month>Feb</month>
<day>1</day>
<data>2180</data>
</r>
<r>
<year>2009</year>
<month>Feb</month>
<day>2</day>
<data>2280</data>
</r>
<r>
<year>2009</year>
<month>Feb</month>
<day>3</day>
<data>2380</data>
</r>
<r>
<year>2010</year>
<month>Jan</month>
<day>1</day>
<data>1181</data>
</r>
<r>
<year>2010</year>
<month>Jan</month>
<day>2</day>
<data>1281</data>
</r>
<r>
<year>2010</year>
<month>Jan</month>
<day>3</day>
<data>1381</data>
</r>
<r>
<year>2010</year>
<month>Feb</month>
<day>1</day>
<data>2181</data>
</r>
<r>
<year>2010</year>
<month>Feb</month>
<day>2</day>
<data>2281</data>
</r>
<r>
<year>2010</year>
<month>Feb</month>
<day>3</day>
<data>2381</data>
</r>

now, i use this sql:

SELECT X.year, x.month, sum(x.data) as sumMonth
FROM xmltest, 
XMLTABLE ('$d/cdata/r' passing xmldoc as "d" 
   COLUMNS 
  year integer path 'year',
  month varchar(3) path 'month',
  day varchar(2) path 'day',
  data float path 'data'
  ) AS X
group by x.year, x.month

order by x.year, x.month

i can get the sum of ‘data’ by each month in each year from this sql and the question i would like to know is how to display the sum of each year after the column sumMonth and just modify this sql but not use two or more sql to get the aggregation of month and year in same time.

the output maybe like this:

year month  sumMonth sumYear
2009  Jan    3840     10680
2009  Feb    6840     10680
2010  Jan    3843     10686
2010  Feb    6843     10686

thanks everyone gave me the answer 🙂

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1 Answer

  1. Editorial Team

    You could use an analytic function:

    SELECT v.YEAR, v.MONTH, v.sumMonth, 
       SUM(v.sumMonth) over(PARTITION BY v.YEAR) sumYear
  FROM (SELECT X.YEAR, x.MONTH, SUM(x.data) AS sumMonth
           FROM xmltest,
                XMLTABLE('$d/cdata/r' passing xmldoc AS "d" 
                  COLUMNS YEAR INTEGER path 'year',
                          MONTH VARCHAR(3) path 'month',
                          DAY VARCHAR(2) path 'day',
                          data FLOAT path 'data') AS X
          GROUP BY x.YEAR, x.MONTH) v
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