Question

#!bin/bash
echo enter your password :
read password

passlength=$(echo ${#password})

if [ $passlength -le 8 ];
then
    echo you entered correct  password
else
    echo entered password is incorrect
fi

if [[$password == [a-z]*[0-9][a-z]*]];
then
    echo match found
else
    echo match not found
fi

I am not getting what’s wrong with this code. If I enter any string as a password, let’s say hello123, it gives me an error:

hello123 : command not found

What is wrong with my script?

Answer 1

You can do the following to make it work cross-platforms with any the bourne shell (/bin/sh) based shell, no bash specific primitives –

echo "$password" | grep -q "[a-z]*[0-9][a-z]*"
if [ $? -eq 0 ] ;then
    echo "match found"
else
    echo "match not found"
fi

Also feel free to use quotes around the variable names. It will save you hours and hours worth of useless debugging. 🙂