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Home/ Questions/Q 8600127
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Editorial Team
  • 0
Editorial Team
Asked: June 12, 20262026-06-12T01:32:52+00:00 2026-06-12T01:32:52+00:00

#!/bin/bash if [ -z $1 ] then echo No argument supplied exit fi if

  • 0
#!/bin/bash

if [ -z "$1" ]
  then
    echo "No argument supplied"
    exit
fi

if [ "$1"="abc" ] ; then
abc
exit
fi

if [ "$1" = "def" ]; then
def
exit 1
fi

function abc()
{
    echo "hello"
}

function def()
{
    echo "hi"
}

Here abc is a function which has local definition. But Bash is giving error “./xyz.sh: line 10: abc: command not found”. Please give me any Solution?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-12T01:32:53+00:00Added an answer on June 12, 2026 at 1:32 am

    All functions must be declared before they can be used, so move your declarations to the top.

    Also, you need to have a space on either side of the = in your string comparison test.

    The following script should work:

    #!/bin/bash
    
    function abc()
    {
        echo "hello"
    }
    
    function def()
    {
        echo "hi"
    }
    
    if [ -z "$1" ]
      then
        echo "No argument supplied"
        exit
    fi
    
    if [ "$1" = "abc" ] ; then
       abc
       exit
    fi
    
    if [ "$1" = "def" ]; then
       def
       exit 1
    fi
    
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