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Home/ Questions/Q 8797297
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T23:49:35+00:00 2026-06-13T23:49:35+00:00

#!/bin/bash index=101,102,103,104,105 /bin/echo $index | /bin/awk -F\, ‘{print $2}’ above is my shell script,(this

  • 0
#!/bin/bash

index=101,102,103,104,105
/bin/echo "$index" | /bin/awk -F\, '{print $2}'

above is my shell script,(this is just a demo It should not be static) when I execute this It returns me value “102” it is right.

 #!/bin/bash

index=101,102,103,104,105

for i in 1 2 3 4 5
do
/bin/echo "$index" | /bin/awk -F\, '{print $i}'
done

I want to print all numbers one by one…where I am wrong ?

I have made some changes with “null” saprated values…Now what changes I suppose to make?
to get and increment values of $i ?

output of  *some command*
1013
1023
12324
13224
3122
2421

#!/bin/bash
index=*some command*
i=1

for LINE in ${OUTPUT} ; do
    ans=$(/bin/echo "$index" | /bin/awk -vRS= -vFS="\n" '{print $i}')
    i=`expr $i + 1`
done
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  1. Editorial Team
    Editorial Team
    2026-06-13T23:49:36+00:00Added an answer on June 13, 2026 at 11:49 pm

    Use double quotes so $i gets expanded by the shell. You have to quote the dollar sign, then, to prevent the expansion of $$:

    awk -F, "{print \$$i}"
    
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