#! /bin/sh VAR=(fdf fef fef) for i in ${VAR}; do echo i; done Code

Question

Asked: May 30, 20262026-05-30T14:55:27+00:00 2026-05-30T14:55:27+00:00

#! /bin/sh

VAR=(fdf fef fef)

for i in ${VAR}; do
        echo i;
done

Code above has errors. I want to make shell take VAR as a separate string array, and get the output like this:

fdf
fef
fef

how to make it happen ? Thanks !

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Editorial Team · Answer 1 · 2026-05-30T14:55:28+00:00

Editorial Team

Try this:

VAR=(aa bb cc)

for i in "${VAR[@]}"
do
        echo $i;
done

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