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Editorial Team
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Asked: 2026-05-13T23:37:24+00:00

<body> <div id=header> <div class=title>SPORTS STORE</div> </div> <div id=categories> <% Html.RenderAction(Menu, Nav); %> </div>

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<body>
<div id="header">
<div class="title">SPORTS STORE</div>
</div>
<div id="categories">
<% Html.RenderAction("Menu", "Nav"); %>
</div>
<div id="content">
<asp:ContentPlaceHolder ID="MainContent" runat="server" />
</div>
</body>

This is a sample code from Steven Sandersons’ book “Pro ASP.NET MVC Framework.”

This code works with MVC V1 and MvcContrib. What it does, it renders a “Menu()” view of “Nav : Controller”. Since ASP.NET MVC V2 includes the Partial() and RenderPartial() functionality, I tried to implement it, but this code doesn’t work. I tried to modify it in several ways, but it seems there’s no overload function that renders partial views, taking as parameters:
1) Controller name
2) View name

I’m sure I’m not the first person who is implementing RenderAction() in this way, so, there must be a workaround. Please help.

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1 Answer

  1. Editorial Team

    I found the problem. I always remove {controller}/{action} route and customize all my routes with lowercase REST like URLs. But for Html.RenderAction it is necessary to have such general route. I added that general route to the end of my routes list and it worked. – Mahdi Feb 22 at 14:42

    Although i still don’t understand, how EXACTLY this works, why is suck route nessesary, and what are route’s constraints. Maybe i will do some research later.

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