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Home/ Questions/Q 7403569
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Editorial Team
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Editorial Team
Asked: May 29, 20262026-05-29T05:07:11+00:00 2026-05-29T05:07:11+00:00

bool is_sentinel() const { return milliseconds==~uintmax_t(0); } I have found this line of code

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bool is_sentinel() const
{
    return milliseconds==~uintmax_t(0);
}

I have found this line of code in thread_data.hpp, I am wondering why is it ~uintmax_t(0) instead of -1 ?

EDIT:

if reason is to avoid compiler warnings, why don’t use :

std::numeric_limits(decltype(milliseconds)>::max()

?

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  1. Editorial Team
    Editorial Team
    2026-05-29T05:07:14+00:00Added an answer on May 29, 2026 at 5:07 am

    One reason for using uintmax_t in the first place is that we don’t know what the largest type is. Is it unsigned long or unsigned long long?

    My guess is that using ~uintmax_t(0) to produce a large unsigned value simply produces the least number of warnings on the largest number of compilers.

    It is common for compilers to warn if you mix signed and unsigned values, or that using a minus on an unsigned value (-1ull) surprisingly(?) gives an unsigned result.

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