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Home/ Questions/Q 6692959
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T05:55:40+00:00 2026-05-26T05:55:40+00:00

Boost has something like this: void OnAccept( const boost::system::error_code & ec) { if( ec

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Boost has something like this:

void OnAccept( const boost::system::error_code & ec)
{
        if( ec )
        {
         ...
        }
}

error_code is a class. What operator to override to make a class object

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  1. Editorial Team
    Editorial Team
    2026-05-26T05:55:40+00:00Added an answer on May 26, 2026 at 5:55 am

    You should use the safe bool idiom. This protects from most pitfalls that occur when you simply provide a conversion to bool.

    To provide some context: If a type can be implicitly converted to bool through operator bool() const, a value of that type can be used in comparison expressions where this conversion doesn’t make any sense. The C++11 solution would be an explicit conversion operator.

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