Question

Boost range library (http://www.boost.org/doc/libs/1_35_0/libs/range/index.html) allows us to abstract a pair of iterators into a range. Now I want to combine two ranges into one, viz:

given two ranges r1 and r2, define r which traverses [r1.begin(), r1.end()[ and then [r2.begin(), r2.end()[. Is there some way to define r as a range using r1 and r2?

Answer 1

I needed this again so I had a second look. There is a way to concat two ranges using boost/range/join.hpp. Unluckily the output range type is not included in the interface:

#include "boost/range/join.hpp"
#include "boost/foreach.hpp"
#include <iostream>

int main() {
        int a[] = {1, 2, 3, 4};
        int b[] = {7, 2, 3, 4};

        boost::iterator_range<int*> ai(&a[0], &a[4]);
        boost::iterator_range<int*> bi(&b[0], &b[4]);
        boost::iterator_range<
           boost::range_detail::
           join_iterator<int*, int*, int, int&, 
           boost::random_access_traversal_tag> > ci = boost::join(ai, bi); 

        BOOST_FOREACH(int& i, ci) {
                std::cout << i; //prints 12347234
        }
}

I found the output type using the compiler messages. C++0x auto will be relevant there as well.