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Home/ Questions/Q 944029
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T22:31:36+00:00 2026-05-15T22:31:36+00:00

boost::tuple has a get() member function used like this: tuple<int, string, string> t(5, foo,

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boost::tuple has a get() member function used like this:

tuple<int, string, string> t(5, "foo", "bar");
cout << t.get<1>();  // outputs "foo"

It seems the C++0x std::tuple does not have this member function, and you have to instead use the non-member function form:

std::get<1>(t);

which to me looks uglier.

Is there any particular reason why std::tuple doesn’t have the member function? Or is it just my implementation (GCC 4.4)?

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  1. Editorial Team
    Editorial Team
    2026-05-15T22:31:37+00:00Added an answer on May 15, 2026 at 10:31 pm

    From C++0x draft:

    [ Note: The reason get is a nonmember function is that if this functionality had been provided as a member function, code where the type depended on a template parameter would have required using the template keyword. — end note ]

    This can be illustrated with this code:

    template <typename T>
    struct test
    {
      T value;
      template <int ignored>
      T&  member_get ()
      {  return value;  }
    };
    
    template <int ignored, typename T>
    T&  free_get (test <T>& x)
    {  return x.value;  }
    
    template <typename T>
    void
    bar ()
    {
      test <T>  x;
      x.template member_get <0> ();  // template is required here
      free_get <0> (x);
    };
    
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