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Home/ Questions/Q 8069581
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Editorial Team
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Editorial Team
Asked: June 5, 20262026-06-05T13:05:46+00:00 2026-06-05T13:05:46+00:00

Both list and islice objects are iterable but why this difference in result. r

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Both list and islice objects are iterable but why this difference in result.

r = [1, 2, 3, 4]               
i1, i2 = tee(r)
print [e for e in r if e < 3]
print [e for e in i2]
#[1, 2]
#[1, 2, 3, 4]


r = islice(count(), 1, 5)          
i1, i2 = tee(r)
print [e for e in r if e < 3]
print [e for e in i2]
#[1, 2]
#[]
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-05T13:05:48+00:00Added an answer on June 5, 2026 at 1:05 pm

    The issue here is that tee() needs to consume the values from the original iterator, if you start consuming them from the original iterator, it will be unable to function correctly. In your list example, the iteration simply begins again. In the generator example, it is exhausted and no more values are produced.

    This is well documented:

    Once tee() has made a split, the original iterable should not be used anywhere else; otherwise, the iterable could get advanced without the tee objects being informed.

    Source

    Edit to illustrate the point in the difference between a list and a generator:

    >>> from itertools import islice, count
    >>> a = list(range(5))
    >>> b = islice(count(), 0, 5)
    >>> a
    [0, 1, 2, 3, 4]
    >>> b
    <itertools.islice object at 0x7fabc95d0fc8>
    >>> for item in a:
    ...     print(item)
    ... 
    0
    1
    2
    3
    4
    >>> for item in a:
    ...     print(item)
    ... 
    0
    1
    2
    3
    4
    >>> for item in b:
    ...     print(item)
    ... 
    0
    1
    2
    3
    4
    >>> for item in b:
    ...     print(item)
    ... 
    >>> 
    
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