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Home/ Questions/Q 4615842
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T01:53:51+00:00 2026-05-22T01:53:51+00:00

Both of these code blocks below alert foo then bar . The only difference

  • 0

Both of these code blocks below alert foo then bar. The only difference is })() and }()).

Code 1:

(function()
{
    bar = 'bar';
    alert('foo');
})();

alert(bar);

Code 2:

(function()
{
    bar = 'bar';
    alert('foo');
}());

alert(bar);

So is there any difference, apart from the syntax?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-22T01:53:52+00:00Added an answer on May 22, 2026 at 1:53 am

    No; they are identical


    However, if you add new beforehand and .something afterwards, they will be different.

    Code 1

    new (function() {
        this.prop = 4;
    }) ().prop;
    

    This code creates a new instance of this function’s class, then gets the prop property of the new instance.
    It returns 4.

    It’s equivalent to

    function MyClass() {
        this.prop = 4;
    }
    new MyClass().prop;
    

    Code 2

    new ( function() {
        return { Class: function() { } }; 
    }() ).Class;
    

    This code calls new on the Class property.
    Since the parentheses for the function call are inside the outer set of parentheses, they aren’t picked up by the new expression, and instead call the function normally, returning its return value.
    The new expression parses up to the .Class and instantiates that. (the parentheses after new are optional)

    It’s equivalent to

    var namespace = { Class: function() { } };
    
    function getNamespace() { return namespace; }
    
    new ( getNamespace() ).Class;
    //Or,
    new namespace.Class;
    

    Without the parentheses around the call to getNamespace(), this would be parsed as (new getNamespace()).Class — it would call instantiate the getNamespace class and return the Class property of the new instance.

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