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Home/ Questions/Q 687451
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T02:07:42+00:00 2026-05-14T02:07:42+00:00

Boy, this one is really weird. I expect the following code to print 1990,

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Boy, this one is really weird. I expect the following code to print 1990, but it prints 1989!

$val = '$19.9';

$val = preg_replace('/[^\d.]/','',$val);
$val = intval($val * 100);

echo $val;

Why on earth is this happening?

Edit: and this code:

$val = '$19.9';
$val = preg_replace('/[^\d.]/','',$val);
echo $val . "<br>";
$val = $val * 100;
echo $val . "<br>";
$val = intval($val);
echo $val;

Prints:

19.9
1990
1989

Why does intval(1990) equal 1989???

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-14T02:07:42+00:00Added an answer on May 14, 2026 at 2:07 am

    This is a precision issue inherent to floating point numbers in PHP, and lots of other languages. This bug report discusses it a bit, in the context of casting as an int:

    http://bugs.php.net/bug.php?id=33731

    Try round($val * 100) instead.

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