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Home/ Questions/Q 8991587
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T22:45:48+00:00 2026-06-15T22:45:48+00:00

$(#btnGall).click(function() { $(‘#gall’).slideToggle(‘slow’); $(#gInfo).show(); }); Why this code executes firstly the second line, and

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$("#btnGall").click(function() {
    $('#gall').slideToggle('slow');
    $("#gInfo").show();
});

Why this code executes firstly the second line, and then the first one.
I don’t want to show #gInfo before slideToggle is finished.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-15T22:45:49+00:00Added an answer on June 15, 2026 at 10:45 pm

    Call the function from an anonymous function specified as the success callback passed into the slidetoggle function.

    $("#btnGall").click(function() {
        $('#gall').slideToggle('slow', function(){
            $("#gInfo").show();
        });
    });
    

    SlideToggle Documentation

    Working Example: http://jsfiddle.net/2zn6G/

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