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Home/ Questions/Q 256763
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Editorial Team
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Editorial Team
Asked: May 11, 20262026-05-11T22:02:28+00:00 2026-05-11T22:02:28+00:00

Building off Does Perl have an enumeration type? , how can I perform dynamic

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Building off Does Perl have an enumeration type?, how can I perform dynamic type checking (or static type checking if use strict is able to do so) that my subroutine argument is getting the right type of enum?

package Phone::Type;

use constant {
    HOME => 'Home',
    WORK => 'Work',
};

package main;

sub fun
{
    my ($my_phone_type_enum) = @_;
    # How to check my_phone_type_enum, is either Phone::Type->HOME or Phone::Type->WORK or ... but not 'Dog' or 'Cat'?
}

fun(Phone::Type->HOME); # valid
fun(Phone::Type->WORK); # valid
fun('DOG');             # run-time or compile time error
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-11T22:02:28+00:00Added an answer on May 11, 2026 at 10:02 pm

    Here is one way:

    #!/usr/bin/perl
    
    package Phone::Type;
    
    use strict;
    use warnings;
    
    use constant {
        HOME => 'Home',
        WORK => 'Work',
    };
    
    package main;
    
    use strict;
    use warnings;
    
    sub fun {
        my ($phone_type) = @_;
        Phone::Type->can( $phone_type )
            or die "'$phone_type' is not valid\n";
    }
    
    fun('HOME'); # valid
    fun('WORK'); # valid
    fun('DOG');  # run-time or compile time error
    __END__
    
    C:\Temp> dfg
    'DOG' is not valid
    
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