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Editorial Team
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Asked: 2026-05-28T05:30:12+00:00

<button class=addToPlaylist onclick=javascript:myPopup(<?php echo $videos[$counter]?>); return false;>+</button> I have a button on an image

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<button class="addToPlaylist" onclick="javascript:myPopup(<?php echo $videos[$counter]?>);
return false;">+</button>

I have a button on an image as a html hyperlink. I want to perform different actions on hyperlink and button. The above code works whenever I do not pass the PHP variable using echo. When i pass PHP variable, the button also performs the same action as of the hyperlink, that means return false does not work.

Any idea why the return false; does not work when i pass PHP variable?

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1 Answer

  1. Editorial Team

    This should be:

    <button class="addToPlaylist" onclick="javascript:myPopup('<?php echo $videos[$counter];?>');return false;">+</button>

    Note the single quotes in myPopup. As you pass a string to myPopup, you will need to enclose it with single quotes. (Double won’t work as there is already double quotes for the onclick)

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