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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T07:50:31+00:00 2026-05-15T07:50:31+00:00

<Button Name=btnFoo Content=Foo > <Button.ContextMenu Placement=Bottom PlacementTarget=btnFoo> <MenuItem Header=Bar /> </Button.ContextMenu> </Button> gives me

  • 0
<Button Name="btnFoo" Content="Foo" >
    <Button.ContextMenu Placement="Bottom" PlacementTarget="btnFoo">
        <MenuItem Header="Bar" />
    </Button.ContextMenu>
</Button>

gives me a runtime error ‘UIElement’ type does not have a public TypeConverter class

I also tried

<Button Name="btnFoo" Content="Foo" >
    <Button.ContextMenu Placement="Bottom" PlacementTarget="{Binding ElementName=btnFoo}">
        <MenuItem Header="Bar" />
    </Button.ContextMenu>
</Button>

and that put the ContextMenu in the top left corner of my screen, rather than at the Button

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-15T07:50:32+00:00Added an answer on May 15, 2026 at 7:50 am

    You should be setting the ContextMenuService.Placement attached property on the button, as stated in the remarks in the documentation for ContextMenu.Placement.

    <Button Name="btnFoo" Content="Foo" ContextMenuService.Placement="Bottom">
        <Button.ContextMenu>
            <ContextMenu>
                <MenuItem Header="Bar" />
            </ContextMenu>
        </Button.ContextMenu>
    </Button>
    
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