Question

By default the BinaryWriter class writes int values with the low bits on the left (e.g. (int)6 becomes 06 00 00 00 when the resulting file is viewed in a hex editor). I need the low bits on the right (e.g. 00 00 00 06).

How do I achieve this?

EDIT: Thanks strager for giving me the name for what I was looking for. I’ve edited the title and tags to make it easier to find.

Answer 1

Jon Skeet has an EndianBitConverter here that should do the job. Just use big/little endian as desired. Alternatively, just shift the data a few times ;-p

        int i = 6;         byte[] raw = new byte[4] {             (byte)(i >> 24), (byte)(i >> 16),             (byte)(i >> 8), (byte)(i)};