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Home/ Questions/Q 6922419
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T10:24:12+00:00 2026-05-27T10:24:12+00:00

By using Alert on the response paramater after a jquery success will display the

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By using Alert on the response paramater after a jquery success will display the values I need, and the problem is picking them out with k/v. I don’t know if this is some incompatibily issue with json format or what, from php. Either nothing happens (no Alert) or the alert will say ‘undefined’ if I attempt to get values by using the keys to them.

Relevant code:

JQuery:

var curr = $(this).val();
// alert(curr);
$.ajax({
type: 'GET',
url: 'CurrencyResponse.php?q='+curr,
contentType: "application/json; charset=utf-8",
success: function(response) {
var items = response.d;
// alert(response); this will display some json key value from server
$.each(items, function (index, item) {
// alert(item.msg); or updating some div tag here, eventless
});
},

PHP:

<?php
// $query = parse_url($_SERVER['REQUEST_URI'], PHP_URL_QUERY);
// $query = $_GET["q"];
$response = array();
$response["msg"] = "Hjksa!";
$response["nok"] = "9.32";

echo json_encode($response);
?>

Help here will be much appreciated! =)

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T10:24:13+00:00Added an answer on May 27, 2026 at 10:24 am

    Use the dataType parameter for jQuery’s AJAX, like so:

    $.ajax({
        type: 'GET',
        url: 'CurrencyResponse.php?q='+curr,
        dataType: 'json',
        success: function( json) {
            alert( json.msg); // Will output Hjksa!
    
        }
    });
    

    This tells jQuery that the response from the server is JSON, and that it should return a JSON object to the callback functions that take the server response as their parameters.

    Read more about dataType on jQuery’s site.

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