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Home/ Questions/Q 4107982
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T21:35:23+00:00 2026-05-20T21:35:23+00:00

C++ newbie here. I am a science guy writing a cfd (ish) code. I

  • 0

C++ newbie here.

I am a science guy writing a cfd (ish) code. I have created a class for all solving functions, and one that handles operations on a grid. The grid class wants to be able to see a few of the variables stored in the solving class, as passing them all to the grid class seems like a bit of effort.

So in my research I came across friend classes, but can’t seem to get it to work. Please see the fully cut back example below. Class A is the solver, and it creates a grid class B. Even though I have written friend class B, I still get the following compile error (g++):

In member function ‘void B::testB()’:

error: ‘a1’ was not declared in this scope

Here is the code:

#include <iostream>
using namespace std;
class B {
private:
    int b1;

public:
    void testB(){
        cout<<a1<<endl;
    };  


};

class A {
friend class B;

private:
    int a1;

public:
    void testA(){
        a1=2;
        B b;
        b.testB();
        };
};


int main(){
    A a;
    a.testA();
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-20T21:35:23+00:00Added an answer on May 20, 2026 at 9:35 pm

    a1 only exists as a part of instances of class A. In other words, you need an A object in order to access a1.

    EDIT:
    but it turns out that wasn’t the only problem in the source you gave.

    This works:

    #include <iostream>
    using namespace std;
    
    class B;
    
    class A {
      friend class B;
      private:
        int a1;
      public:
        void testA();
    };
    
    class B {
    private:
        int b1;
    
    public:
        void testB(A *a){
            cout << (a->a1) << endl;
        }
    };
    
    void A::testA() {
        this->a1 = 2;
        B b;
        b.testB(this);
    }
    
    
    int main(){
        A a;
        a.testA();
    }
    
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