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Home/ Questions/Q 3669298
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Editorial Team
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Editorial Team
Asked: May 19, 20262026-05-19T02:13:34+00:00 2026-05-19T02:13:34+00:00

c++ (Ubuntu/Linaro 4.4.4-14ubuntu5) 4.4.5 I am converting some source code from windows to running

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c++ (Ubuntu/Linaro 4.4.4-14ubuntu5) 4.4.5

I am converting some source code from windows to running on ubuntu.

However, the windows is using the code below to log messages and get the current time the message is logged. However, this is windows. What is the best way to convert this to running on linux?

struct  _timeb timebuffer;
char    *timeline;

_ftime(&timebuffer);
timeline = ctime(&(timebuffer.time));

Many thanks for any advice,

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  1. Editorial Team
    Editorial Team
    2026-05-19T02:13:35+00:00Added an answer on May 19, 2026 at 2:13 am

    in linux a similar function ftime is used which gives you the time do

     #include <sys/timeb.h>
     /* .... */
     struct timeb tp;
     ftime(&tp);
     printf("time = %ld.%d\n",tp.time,tp.millitm);
    

    this will give you the time in second and milliseconds.

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