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Home/ Questions/Q 7054759
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T03:39:58+00:00 2026-05-28T03:39:58+00:00

Calling : $.ajax({ type: POST, url: ‘http://blahblah/cow.php’, contentType: application/json, data: { ‘guid’: ‘111’, ‘score’:

  • 0

Calling :

 $.ajax({
        type: "POST",
        url: 'http://blahblah/cow.php',
        contentType: "application/json",
        data: {
            'guid': '111',
            'score': 592,
            'initials': 'tod'
        },
        success: function (data) {

            try {
                //alert(data + " -- " + data.length);
                if (data.length > 0) {

Doing this in my php page:

echo ('[{error : "' . $error . '", rank : "' . $usersRank . '", totalScores : "' . $totalScores . '"}]');

But JQ just keeps seeing this as text and won’t recognize it as JSON… what am I doing wrong?

Ive tried getting rid of square brackets (nothing), using json_encode – but that was adding quotes to my variables and it still didnt work, tried adding headers(COntent type) to the php page… Argh! Cant figure this out!

DO I HAVE TO CALL DIE or something like that (kind of like Response.end)?

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  1. Editorial Team
    Editorial Team
    2026-05-28T03:39:58+00:00Added an answer on May 28, 2026 at 3:39 am

    I don’t know what I am doing wrong but I finally just did this… I stopped using Content-type in php or dataType in ajax call and just took the data ‘string’ and called

    var obj = jQuery.parseJSON(data);
    

    on it and then perform what I wanted to on it.

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