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Home/ Questions/Q 6026525
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T04:27:29+00:00 2026-05-23T04:27:29+00:00

Can a JavaScript function take unlimited arguments? Something like this: testArray(1, 2, 3, 4,

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Can a JavaScript function take unlimited arguments?
Something like this:

testArray(1, 2, 3, 4, 5...);

I am trying:

var arr = [];
function testArray(A) {
    arr.push(A);
}

But this doesn’t work (output is only the first argument). Or the only way is:

function testArray(a, b, c, d, e...) {

}

Thanks

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-23T04:27:29+00:00Added an answer on May 23, 2026 at 4:27 am

    There’s a weird “magic” variable you can reference called “arguments”:

    function manyArgs() {
      for (var i = 0; i < arguments.length; ++i)
        alert(arguments[i]);
    }
    

    It’s like an array, but it’s not an array. In fact it’s so weird that you really shouldn’t use it much at all. A common practice is to get the values of it into a real array:

    function foo() {
      var args = Array.prototype.slice.call(arguments, 0);
      // ...
    

    In that example, “args” would be a normal array, without any of the weirdness. There are all sorts of nasty problems with “arguments”, and in ECMAScript 5 its functionality will be curtailed.

    edit — though using the .slice() function sure is convenient, it turns out that passing the arguments object out of a function causes headaches for optimization, so much so that functions that do it may not get optimized at all. The simple, straightforward way to turn arguments into an array is therefore

    function foo() {
      var args = [];
      for (var i = 0; i < arguments.length; ++i) args[i] = arguments[i];
      // ...
    }
    

    More about arguments and optimization.

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