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Home/ Questions/Q 7627207
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T05:25:44+00:00 2026-05-31T05:25:44+00:00

Can Anybody explain why this happen? This is my code in a plugin called

  • 0

Can Anybody explain why this happen?

This is my code in a plugin called something:

(function($){
$.fn.extend({
    something: function(options) {
       // Here I define defaults
       $(this).bind('change', function () { 
          return $(this).each(function() {
          // a function body
          });
       });
     }
});
})(jQuery);

and I call this plugin in another js like this:

var myarray=new Array();
myarray[0] = $('#selector').something({
regex:/^([\u0600-\u06FF]|\s)*$/,
    // another options
    });
$('#selector').change(function (){
    alert (myarray[0]);
});

in every change in my selector it returns me undefined.

It completely make me insane. Thanks if anyone can help me.

Edit:

You Can Read My complete code here.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-31T05:25:44+00:00Added an answer on May 31, 2026 at 5:25 am

    In your plugin you are just attaching a change event handler on the element which just runs a loop on all the matched set of elements and returns a jQuery object.

    If you want to return something from something plugin then the return statement should be outside the event handler.

    $.fn.extend({
        something: function(options) {
              return $(this).each(function() {
                   //Do processing here
              });
         }
    });
    

    Now you can use this

    var myarray = $('#selector').something({
            regex:/^([\u0600-\u06FF]|\s)*$/,
            // another options
    });
    $('#selector').change(function (){
        alert (myarray[0]);
    });
    

    Note that myarray will be an array because jQuery each returns a jQuery object which itself is an array of DOM elements.

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