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Home/ Questions/Q 6009321
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T01:57:14+00:00 2026-05-23T01:57:14+00:00

Can anybody give me an intuitive explanation of why the Ackermann function http://en.wikipedia.org/wiki/Ackermann_function is

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Can anybody give me an intuitive explanation of why the Ackermann function http://en.wikipedia.org/wiki/Ackermann_function is related to the amortized complexity of union-find algorithm used for disjoint sets http://en.wikipedia.org/wiki/Disjoint-set_data_structure?

The analysis in Tarjan’s data structure book isn’t very intuitive.

I also looked it up in Introduction to Algorithms, but it also seems too rigorous and non-intuitive.

Thanks for your help!

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  1. Editorial Team
    Editorial Team
    2026-05-23T01:57:15+00:00Added an answer on May 23, 2026 at 1:57 am

    Applied to Disjoint-set forests

    from Wikipedia

    (about find and union) These two
    techniques complement each other;
    applied together, the amortized time
    per operation is only O(α(n)), where
    α(n) is the inverse of the function
    f(n) = A(n,n), and A is the extremely
    quickly-growing Ackermann function.
    Since α(n) is the inverse of this
    function, α(n) is less than 5 for all
    remotely practical values of n. Thus,
    the amortized running time per
    operation is effectively a small
    constant.

    So why Ackerman?

    from Kruskal algoritm

    The Function lg*n

    Note that lg*n is a very slow growing
    function, much slower than lg n. In
    fact is slower than lg lg n, or any
    finite composition of lg n. It is the
    inverse of the function f(n) = 2
    ^2^2^…^2, n times. For n >= 5, f(n)
    is greater than the number of atoms in
    the universe. Hence for all intents
    and purposes, the inverse of f(n) for
    any real life value of n, is constant.
    From an engineer’s point of view,
    Kruskal’s algorithm runs in O(e).
    Note of course that from a
    theoretician’s point of view, a true
    result of O(e) would still be a
    significant breakthrough. The whole
    picture is not complete because the
    actual best result shows that lg*n can
    be replaced by the inverse of A(p,n)
    where A is Ackermann’s function, a
    function that grows explosively. The
    inverse of Ackermann’s function is
    related to lg*n, and is a nicer
    result, but the proof is even
    harder.

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