Question

can anybody let me know why array_search doesnt works for me? All i want is to search value and and get corresponding key value
for eg if i search wiliam i should get 4.. Its simple but aint working for me

<?php
$fqlResult[0]['uid']='1';
$fqlResult[0]['name']='Jay';
$fqlResult[1]['uid']='2';
$fqlResult[1]['name']='UserName2';
$fqlResult[2]['uid']='3';
$fqlResult[2]['name']='Frances';
$fqlResult[3]['uid']='4';
$fqlResult[3]['name']='William';



        for($i=0;$i<count($fqlResult);$i++)
        {

            $userdbname="'".$fqlResult[$i]['name']."'";
            $userdb[$userdbname]="'".$fqlResult[$i]['uid']."'"; 

        }


echo "<pre>";
print_r($userdb);
echo "</pre>";
echo array_search('4', $userdb);
?>

Answer 1

It doesn’t work because array_seach searches values and “William” is a key. To complicate things, your values and keys are wrapped in single quotes during the for loop.

You’d want to do something like this:

if ( ! empty($userdb["'William'"]) )
{
  // Echoes "'4'"
  echo $userdb["'William'"];
}

// To find user ID "'4'"
// Outputs "'William'"
echo array_search("'4'", $userdb);

If you don’t want things wrapped in single quotes, you’ll need to change your for loop as follows:

for($i=0;$i<count($fqlResult);$i++)
{
  $userdbname=$fqlResult[$i]['name'];
  $userdb[$userdbname]=$fqlResult[$i]['uid']; 
}

if ( ! empty($userdb["William"]) )
{
  // Outputs "4" (without the single quotes)
  echo $userdb["William"];
}

// To find user ID "4" (without the single quotes)
// Outputs "William"
echo array_search('4', $userdb);